(x+y+2z)^2 using identity
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We know the algebraic identity ,
( a + b + c )² = a²+b²+c²+2ab+2bc+2ca
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Here ,
a = 2x,
b = - y ,
c = z ,
[ 2x + ( -y ) + z ]²
= (2x)²+(-y)²+z²+2(2x)(-y)+2(-y)z+2z(2x)
= 4x² + y² + z² - 4xy - 2yz + 4zx
I hope this helps you.
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