(x+y+2z)^2 USING IDENTITY
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➡ (x + y + 2z)²
- (a + b + c)² = a² + b² + c² + 2[ab + bc + ac]
➡ (x)² + (y)² + (2z)² + 2[(x.y) + (y.2z) + (x.2z)]
➡ x² + y² + 4z² + 2xy + 4yz + 4xz
Step-by-step explanation:
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a ^2+b^2+c^2
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