(x+y+2z)(x²+y²+z²-2xy-2yz-2zx)
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Step-by-step explanation:x + y + z)²
Compare this with (a + b)², whereas { a = x and b = (y + z) }
As we know (a + b)² = a² + b² + 2ab
On Applying formula, we get
(x + y + z)²
=> x² + (y + z)² + 2x(y + z)
=> x² + y² + z² + 2yz + 2xy + 2xz
Hence, proved.
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