Question

(x-y)³ + (2x-y)³ - (3x-2y)³ = ?​

Answer 1

Hey Pritthiraj !

Step-by-step explanation:

To Find :

(x - y)³ + (2x - y)³ - (3x - 2y)³

Formula :

(a - b)³ = a³ - b³ - 3a²b + 3ab²

Procedure :

(x - y)³ = x³ - y³ - 3x²y + 3xy²

(2x - y)³ = 8x³ - y³ - 12x²y + 6xy²

(3x - 2y)³ = 27x³ - 8y³ - 54x²y + 36xy²

Now :

(x - y)³ + (2x - y)³ - (3x - 2y)³

=> (x³ - y³ - 3x²y + 3xy²) + (8x³ - y³ - 12x²y + 6xy²) - (27x³ - 8y³ - 54x²y + 36xy²)

=> (x³ + 8x³ - 27x³) + (- y³ - y³ + 8y³) + (- 3x²y - 12x²y + 54x²y) + (3xy² + 6xy² - 36xy²)

=> -18x³ + 6y³ + 39x²y - 27xy²

OR

=> (- 3)(6x³ - 2y³ - 13x²y + 9xy²)

Thanks !