x+y=3,3x-2y-4=0 by determinant method
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Sol.
x+y =3 ------1)
3x-2y-4 =o
D = | 1 1 0|
| 3. -2 -4|
= 1(-4 -0) - 1( 0 +4) +0
= -4 -4
= -8
Dx =
x+y =3 ------1)
3x-2y-4 =o
D = | 1 1 0|
| 3. -2 -4|
= 1(-4 -0) - 1( 0 +4) +0
= -4 -4
= -8
Dx =
Anonymous:
sorry it's a half answer.
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