Question

x + y = 3,3x - 2y = 4 shade the region of two lines on y axis I want three boxes​

Answer 1

• We draw graphs of the equations x + y = 3 and 3x - 2y = 4. Then locate their point of intersection.
• Recall, that it is enough to know two points to draw a straight line. Consider x+y = 3. Taking x = 0, we get y = 3.
• Taking y 0, we get x 3. Thus (0, 3) and = = (3, 0) are on the straight line x +y = 3. Take a graph paper. Fix your coordinate system x ⇒ y axis on the graph paper. Locate A (3,0) and B = (0, 3) with = respect to this coordinate system. Join A and B and extend it to a straight line.
• Consider the equation 3x - 2y = 4. If we take x = 0, we obtain y = -2. Similarly, 4gives y = 4. Thus C X = = (0, -2) and D = (4,4) are points on the straight line 3x - 2y = 4. Locate these points on the graph paper. Join them and extend to a straight line.
• Now we have two straight line. They intersect at a point E. Looking at the graph, you see that E has coordinates (2,1). Thus = 2 and y = 1 is the solution. We may X = verify it: 2 + 1 = 3 and 3(2) — 2(1) = 6 - 2 = 4.

Answer 2

Step-by-step explanation:

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