(x-y)^3 -3xy(x-y)-15xy-125; where x-y=6
Answers
Answered by
1
Step-by-step explanation:
for(x-y)=6
(x-y)^3-3xy(x-y)-15xy-125
=(6)^3-3xy(6)-15xy-125
=216-18xy-15xy-125
= -33xy+91
Similar questions