Question

(x-y)^3+8(x+y)^3. Factorise the question.

Answer 1

aur bhai Step-by-step explanation:

Answer 2

Answer:

(9x+7y) (x^2 + 3y^2) (y^2 - 3x^2)

Step-by-step explanation:

$=(x-y)^3 + 8(x+y)^3\\= x^3-y^3-3xy(x-y) + 8[x^3+y^3+3xy(x+y)]\\=x^3-y^3-3x^2y+3xy^2 +8(x^3+y^3 +3x^2y +3xy^2)\\=x^3-y^3-3x^2y+3xy^2 + 8x^3 + 8y^3 + 24x^2y + 24xy^2\\=9x^3 + 7y^3-21x^2y+27xy^2\\=9x(x^2+3y^2) + 7y(y^2 - 3x^2)\\=(9x+7y) (x^2 + 3y^2) (y^2-3x^2)$