x+y=3 and 3x-2y=4 by determinant method , vale of D is
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x + y = 3
x + y - 3 = 0
a = 1 , b = 1, c = -3
d = √b² - 4ac
d = √1 - (-12)
d = √1 + 12
d = √13
3x - 2y = 4
3x - 2y - 4 = 0
a = 3, b = -2, c = -4
d = √b² - 4ac
d = √(-2)² - 4(3)(-4)
d = √4 + 48
d = √52
d = √13 × 2 × 2
d = 2√13
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