Question

X+y=3,and XY=2 to x^3-y^3 ka man

Answer 1

Answer:

x + y = 3

x*y = 2

x = 2/y

2/y + y = 3

2 + y^2 = 3y

y^2 - 3y + 2 = 0

y^2 - y - 2y + 2 = 0

y(y-1) - 2(y-1) = 0

y-1 = 0 or y - 2 = 0

y = 1 or y = 2

x = 2 or y = 1

x^3 - y^3 = 2^3 - 1^3 = 8 - 1 = 7

or

1^3 - 2^3 = 1 - 8 = -7

Answer is 7 or -7

Step-by-step explanation:

Answer 2

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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
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First of all, let us calculate the values of some major algebric expressions.

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*⃣*⃣*⃣ CALCULATION - A *⃣*⃣*⃣

(x+y) = 3

=> (x+y)² = (3)²

=> x²+y² = 9 - 2xy

=> x²+y² = 9-4 or 5.

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*⃣*⃣*⃣ CALCULATION - B *⃣*⃣*⃣

(x + y)² = (3)²

=> (x-y)²+4xy = 9

=> (x-y)² = 9-8 or 1

=> (x-y) = √1 or 1.

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THUS, WE CAN APPLY THE FORMULA :

(a³-b³) = (a-b) (a²+ab+b²)

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ON DOING SO, WE GET,

(x³-y³) = (x-y) (x²+xy+y²)

=> (x³-y³) = 1 (5+2)

=> (x³-y³) = 7 [REQUIRED ANSWER]


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⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

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