Question

x+y=3 x^2+y^2=12
2xy=?​

Answer 1

Answer:

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Answer 2

Given:-

x+y =3 (x²+ y²)=12

=>x²+y² = 12/3 = 4

Solution :-

(x+y)²= 12²

x²+y²+2xy= 144

=>4 + 2xy= 144

=>2xy = 144-4

=>2xy = 140