Question

x-y=3 , x/3+y/2=6 (subs)

Answer 1

Step-by-step explanation:

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Answer 2

x−y=3-----(1)

$\frac{x}{3} + \frac{y}{2} = 6 - - - - - (2)$

Find the value of x from equation and substitute in equation (2).

x=3+y

Now

$\frac{3x + y}{3} + \frac{y}{2} = 6$

$\frac{6 + 2y + 3y}{6} = 6$

$\implies \: \frac{6 + 5y}{6} = 6$

⇒6+5y=36⇒5y=36−6=30

$y = \frac{30}{5} = 6$

and x=3+y=3+6=9

The value of x is 9 and the value of y is 6.