Math, asked by lollishanker014, 4 months ago

(x-y)^3=x^3-y^3-3xy (x-y)=x^3-y^3-3x^2y+3xy^2​

Answers

Answered by vaishnav210314Danya
0

x

3

+3x

2

y+3xy

2

+y

3

−8

x+y)

3

−8

(x+y)

3

−2

3

(x+y−2){(x+y)

2

+2(x+y)+2

2

}

(x+y−2)(x

2

+y

2

+2x+2y+4+xy)

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