Question

x + y = √3, x-y=0 then x =​

Answer 1

Answer:

If x - y = 0 then what is x + y

Case 1

Step 1

x−y=0 Then

Step 2

x=y So

Step 3

x+y=y+y ( From Step 2 i.e x=y )

So

x+y=2y

CASE 2

Step 1

x−y=0 Then

Step 2

−y=−x

Step 3 [Multiplying Both LHS & RHS by -1]

−yX−1=−xX−1

Step 4

y=x So

Step 5

x+y=x+x [ From Step 4 i.e y = x ]

x+y=2x

After Case 1 & Case 2 we can say that Our

Final Answer Is:

x+y=2x=2y

Case 3

Now, If x−y=0 Then x+y=?

So in this Case We Assume Value of x = 1 & y = 1 [Assuming Same Value As in Case 1 we Have Already Proven x = y]

So, After Evaluating The Equation

x−y=1−1=0Then

x+y=1+1=2

If We Consider Our Final Answer and Input the assumed Value of x & y :

x+y=2x=2y

x+y=2×1=2x1=2

So

X+Y=2 [ If We Assume X = Y =1]

Hence It's Proves That :

Ifx−y=0Thenx+y=2x=2y

Answer 2

Answer:

(x+y)+(x-y) =√3+0=√3

=>2x=√3

=>x=√3/2