Math, asked by kashyapanushka66, 1 month ago

(x+y)^3+(x-y)^3+6x(x^2-y^2)​

Answers

Answered by dishadometi
0

Answer:

6x^3- y^2

Step-by-step explanation:

(x+y)^3+(x-y)^3+6x(x^2-y^2)​

= x^3 + y^3 - x^3 - y^3 + 6x * x^2 -y^2

= x^3 + y^3 - x^3 - y^3 + 6x^3 -y^2

= 6x^3- y^2

Answered by komalsharma150201
0

Step-by-step explanation:

(x+y) ^3 + (x-y) ^3 × (x^2-y^2)

so guys, (a+b) ^3 = a^3 + b^3 + 3ab ( a+b)

(a+b) ^3 = a^3 + b^3 + 3ab ( a+b) (a-b) ^3 = a^3-b^3 - 3ab (a-b)

here a =x and b=y

so,

(x+y) ^3 + (x-y) ^3 × (x^2-y^2)

i hpoe it will help you

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