(x+y)^3+(x-y)^3+6x(x^2-y^2)
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Answer:
6x^3- y^2
Step-by-step explanation:
(x+y)^3+(x-y)^3+6x(x^2-y^2)
= x^3 + y^3 - x^3 - y^3 + 6x * x^2 -y^2
= x^3 + y^3 - x^3 - y^3 + 6x^3 -y^2
= 6x^3- y^2
Answered by
0
Step-by-step explanation:
(x+y) ^3 + (x-y) ^3 × (x^2-y^2)
so guys, (a+b) ^3 = a^3 + b^3 + 3ab ( a+b)
(a+b) ^3 = a^3 + b^3 + 3ab ( a+b) (a-b) ^3 = a^3-b^3 - 3ab (a-b)
here a =x and b=y
so,
(x+y) ^3 + (x-y) ^3 × (x^2-y^2)
i hpoe it will help you
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