Question

(x+y)^3 - (x-y)^3 - 6y (x^2-y^2)
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Answer 1

Answer:

Hope it is helpful

Step-by-step explanation:

$(x + y) ^{3} - ( x - y) ^{3} - 6y(x {}^{2} - y {}^{2} ) \\ =(x + y) ^{3} - (x - y) ^{3} - 6y(x - y)(x + y) \\ = (x + y) ^{3} - (x - y) (x - y) ^{2} + 6y(x + y) \\ = (x + y) { ^3} - (x - y)(x ^{2} + y ^{2} - 2xy + 6xy + 6y ^{2} \\ = (x + y) ^{3 } - (x - y)(x ^{2} + 4y^{2} + 4xy) \\ = x ^{3} + y ^{3} + 3x y^{2} + 3x ^{2} y - x ^{3 } - 7x y^{2} - 4x^{2} y + x ^{2} y + 7y ^{3 } + 4xy ^{2} \\ = 8y ^{3}$

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Answer 2

$\tt\huge\purple{hello!!!}$

HERE IS UR ANSWER

$_____________________________$

=(x+y)3−(x−y)3−6y(x2−y2)

=(x+y)3−(x−y)3−6y(x−y)(x+y)

=(x+y)3−(x−y)((x−y)2+6y(x+y))

=(x+y)3−(x−y)(x2+y2−2xy+6xy+6y2)

=(x+y)3−(x−y)(x2+7y2+4xy)

=x3+y3+3x2y+3xy2−x3−7xy2−4x2y+x2y+7y3+4xy

=8y3