Question

(x-y)3=x3-3x2y+3xy2-y3​

Answer 1

Step-by-step explanation:

${(x - y)}^{3}$

$(x - y)(x - y)(x - y)$

$( {x}^{2} - 2xy + {y}^{2} )(x - y)$

$( {x}^{3} - 2{x}^{2} y + x {y}^{2} - {x}^{2} y + 2x {y}^{2} - {y}^{3} )$

${x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3}$

Hope it will help you.

Plz Mark me as a brainliest answer

thanks you