Question

(x-y)3=x3-y3-3xy(x-y)​

Answer 1

Answer:

To Prove: (x-y)³=x³-y³-3xy(x-y)

Proof:

(x-y)³=(x-y)²(x-y)

=(x-y)(x²-2xy+y²)

= x(x²-2xy+y²)-y(x²-2xy+y²)

= x³-2x²y+xy²-xy²+2xy²-y³

= x³-y³-3x²y+3xy²

=x³-y³-3xy(x-y)

hope this helped you..

pls mark as brainliest..

Step-by-step explanation: