Math, asked by dawoodaleem79, 2 months ago

(X-y)3=x3-y3-3xy(x-y)

Answers

Answered by ma1431138
2

Step-by-step explanation:

(x-y)³=(x-y)(x-y)(x-y)

=(x-y)(x²-xy-xy+y²)

=(x-y)(x²-2xy+y²)

=(x³-2x²y+xy²-x²y+2xy²-y³)

=x³-y³-3x²y+3xy²

=x³-y³-3xy(x-y)

Hence ,(x-y)³=x³-y³-3xy(x-y)

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