Question

X+y=3 xy=6
Find x^3+y^3+4(x-y)^2

Answer 1

Answer:

This is your simple method

Step-by-step explanation:

Hope it's helpful for you

Answer 2

Answer:

-165+16(x+y) ^2

Step-by-step explanation:

or x^3+y^3+4(x-y)^2

or x^3+y^3+(4x-4y)^2

or x^3+y^3+(4x-4y)(4x-4y)

or x^3+y^3+(16x^2-16xy-16xy+16y^2)

or x^3+y^3+(16x^2-32xy+16y^2)

or x^3+y^3+16x^2-32xy+16y^2

or (x+y)^3+16x^2-32×6+16y^2

or (3)^3+16x^2-192+16y^2

or 27+16x^2-192+16y^2

or -165+16x^2+16y^2

or -165+16(x+y)^2