Question

(x -y ) ^3 + (y - z) ^3 +(z-x) ^3​

Answer 1

Answer:

Let a= x-y , b = y-z ,c = z-x

therefore a+b+c = x-y+y-z+z-x =0

we know that if a+b+c=0 ,then

a³+b³+c³= 3abc

hence, (x-y)³+(y-z)³+(z-x)³ = 3(x-y)(y-z)(z-x)

Answer 2

suppose that a = (x -y)³ , b = (y -z)³ and c = (z-x)

Now the formula a³ +b³+ c³ = 3abc