(x - y)3 + (y - z)3 + (z -x)3
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answer for the given problem is given
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let (x-y) be a , (y-z) be b and (z- x) be c
Now it is very clear that a + b+c = 0
therefore a3+b3+c3= 3abc
(x-y)3 + (y-z)3 + (z-x)3 = 3(x-y)(y-z)(z-x)
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