Math, asked by harshajain16, 1 year ago

(x-y)³+(y-z)³+ (z-x)³

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Answered by Arunchauhan1

0

(x-y)³ + (y-z)³ + (z - x)³. ... = 3 (xy - x z -y² + yz) (z -x) ... hence, (x-2y)³ + (2y - 3z)³ + (3z-x)³ = 3 (x -2y) (2y -3z)(3z - x)

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