Math, asked by jeevithak2001, 7 months ago

[(x-y)³+(y-z)³+(z-x)³]÷[9(x-y) (y-z) (z-x) ]

Answers

Answered by vimalmaurya0011

0

Answer:

Just apply the formula of cubes and then multiply 9 from x minus y and whatever you get multiply from the other term and then divide it

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