(x-y)³+(y-z)³+(z-x)³ factories without making cube
Answers
Answered by
2
Answer:
hope it helps you
Step-by-step explanation:
We know
a^3+b^3+c^3=3abc. If a+b+c=0
x-y+y-z+z-x=0
Therefore (x-y) ³ + (y-z) ³ + (z-x) ³=3(x-y)(y-z)(z-x)
Answered by
1
Answer:
here a = x - y
b = y - z
c = z- x
now.... a + b+ c = 0
therefore a³ + b³ + c³ = 3abc
now calculate 3(x-y)(y-z)(z-x)
Similar questions