(x+y/3-z/4)
please solve
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Answer:
How to solve your problem
(
+
3
−
1
⋅
4
)
(x+\frac{y}{3}-1 \cdot \frac{z}{4})
(x+3y−1⋅4z)
Simplify
1
Find common denominator
(
+
3
+
−
4
)
(x+\frac{y}{3}+\frac{-z}{4})
(x+3y+4−z)
(
1
2
1
2
+
4
1
2
+
3
(
−
1
)
1
2
)
(\frac{12x}{12}+\frac{4y}{12}+\frac{3\left(-1\right)z}{12})
(1212x+124y+123(−1)z)
2
Combine fractions with common denominator
(
1
2
1
2
+
4
1
2
+
3
(
−
1
)
1
2
)
(\frac{12x}{12}+\frac{4y}{12}+\frac{3\left(-1\right)z}{12})
(1212x+124y+123(−1)z)
(
1
2
+
4
+
3
(
−
1
)
1
2
)
(\frac{12x+4y+3\left(-1\right)z}{12})
(1212x+4y+3(−1)z)
3
Multiply the numbers
(
1
2
+
4
+
3
(
−
1
)
1
2
)
(\frac{12x+4y+{\color{#c92786}{3}}\left({\color{#c92786}{-1}}\right)z}{12})
(1212x+4y+3(−1)z)
(
1
2
+
4
−
3
1
2
)
(\frac{12x+4y{\color{#c92786}{-3}}z}{12})
(1212x+4y−3z)
Solution
(
1
2
+
4
−
3
1
2
)
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