Question

(x + y) (3x - y + 6)

Answer 1

=3x^2-xy+6y+3xy-y^2+6y
=3x^2-xy+3xy-y^2+6y+6y
=3x^2+2xy-y^2+12y

Answer 2

In accordance with the information provided in the question,

We have find the value of the supplied expression in the above question.

Given the data in question (x + y) (3x - y + 6)

As the given equation is in form of

So, for finding the value of the expression we will first multiply "a" with "c" and "d" and then multiply "b" with "c" and "d", and then add the resultant value.

So, value of expression we will be

So, applying the above condition in given question,

We will get,

$=(x+y)(3x-y+6)\\=3x^{2} +3xy-xy-y^{2} +6x+6y\\=3x^{2} +2xy-y^{2} +6x+6y$

Hence the required result will be $3x^{2} +2xy-y^{2} +6x+6y$.