Question

(x-y) (3x+y) find the product​

Answer 1

Answer:

We have x+y=6 and xy−y−3x+3=0

⇒y(x−1)−3(x−1)=0⇒(x−1)(y−3)=0

Equation of the sides of the triangle are

x+y=6 ...(1)

y=3 ...(2)

x=1 ...(3)

Shaded triangle is right angled at (1,3)

∴ the circumcircle is the circle on (3,3) and (1,5) as ends of a diameter and its equation is

(x−3)(x−1)+(y−3)(y−5)=0

⇒x

2

+y

2

−4x−8y+18=0

Answer 2

Step-by-step explanation:

Above is right...

Hope it helps