x-Y =4 and X Y=12 then find the value of x3-y3
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2
Answer:
x=6 , y=2
6 3- 2 3 = 6-2( 36+12+4)
=4(52)
=208
Answered by
4
Answer: 208.
X^3-Y^3 = (x-y)^3+3xy(x-y)
= 64+144=208
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