x+y=-4,find x^3+y^3-12xy+64=?
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Step-by-step explanation:
x³ + y³ + 12xy - 64
x³ + y³ - 4³ + 3(4xy) (64 = 4³)
(x + y - 4)(x² + y² + 4² - xy - 4y - 4x)
x + y = + 4
( 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)
0 * (x² + y² + 4² - xy - 4y - 4x)
= 0
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