Question

x+y=4 then find the value of x^3 +y^3+12xy -64

Answer 1

(x+y)^3 = x^3+y^3+3xy (x+y)
4^3=x^3+y^3+3xy (4)
64=x^3+y^3+12xy
0=x^3+y^3+12xy-64

Answer 2

Answer:

Step-by-step explanation:

(x+y)=4

cubing both side

(x+y)^3=(4)^3

x^3+y^3+3xy(x+y)=64

x^3+y^3+12xy=64

x^3+y^3+12xy-64=0