Question

X+y=4 x-y=3 find the value 16xy(x2+y2) =?

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Given

x + y = 4 →(1) & x - y = 3 →(2)

Adding both equation, we get

2x = 7

After solving we get the value of x & y ,

x = 7/2 & y = 1/2

Putting value of x & y in 16xy(x² + y²) , we get ,

16 × 7/2 × 1/2[(7/2)² + (1/2)²]

28[49/4 + 1/4]

28[50/4]

7 × 50

350