(x+y)⁴-(x-y)⁴ factories
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Answer:Given x⁴-(x-y)⁴
= (x²)²-[(x-y)²]²
= [x²+(x-y)²][x²-(x-y)²]
/* By algebraic identity:
a²-b² = (a+b)(a-b) */
= [x²+(x-y)²][x+(x-y)][x-(x-y)]
= [x²+(x-y)²][x+x-y)][x-x+ y)]
= [x²+(x-y)²](2x-y)y
Step-by-step explanation:
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