(x+y)^4-(x-y)^4 factorisation
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(x+y)^4 - (x-y) ^4
={(x+y)²}² - {(x-y)²}²
We know that a²-b² =(a+b)(a-b)
So,
{(x+y)² +(x-y)²}{(x+y)²-(x-y)²}
={(x²+2xy+y²)+(x²-2xy+y²)}{(x²+2xy+y²)-(x²-2xy+y²)}
=(x²+2xy+y²+x²-2xy+y²)(x²+2xy+y²-x²+2xy-y²)
=(2x²+2y²)(4xy)
=2(x²+y²)(4xy)
=8xy(x²+y²)
secretgirl69:
tq so much
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