Question

(x + y)4 - (x - y)4 (here 4 is power)in both So factorise​

Answer 1

Step-by-step explanation:

${(x+y)}^{2}-{(x-y)}^{2}$

$=({x}^{2}+2xy+{y}^{2})-({x}^{2}-2xy+{y}^{2})$

$={x}^{2}+2xy+{y }^{2}-{x}^{2}+2xy-{y}^{2}$

$={x}^{2}-{x}^{2}+{y}^{2}-{y}^{2}+2xy+2xy$$=0+0+4xy$

$=4xy$

Extra information:-

used formula:-

${a+b}^{2}={a}^{2}+2ab+{b}^{2}$

${a-b}^{2}={a}^{2}-2ab+{b}^{2}$