Question

x+y = 4 ,xy=2, y+z=5, yz=3, z+x =6 and zx = 4 then find the value of x² + y² + z²-3xy​

Answer 1

Answer:

17.5 or 35/2

Step-by-step explanation:

x+y=4 -(I)

+ x+z=6 -(ii)

-> 2x + y + z = 10

put y+z = 5 in the above equation

2x = 5 -> x = 2.5

Putting in (I), y = 1.5

Putting in (II), z = 4.5

so x^2 + y^2 + z^2 - 3xy = 6.25 + 2.25 + 20.25 - 11.25 = 17.5

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