Math, asked by parzanchiniwala, 6 months ago

x+y=40,x-y=16 elimination​

Answers

Answered by sunilmotihari1969
0

Answer:

x=28

y=12

Step-by-step explanation:

subtract eqn (i) - eqn (ii)

x+y=40

x-y=16

2y=24

y=12

putting the value of y in eqn(ii)

x-y=16

x-12=16

x=28

Hence,

x=28

y=12

I hope it will be helpful for you

Answered by debmohinipatranabish
0

Answer:

Let ,x+y=40......(i)

x-y=16......(ii)

Now, by adding (i) and (ii)

2x=56

x =28

Putting the value of x in (i)

x+y=40

28+y=40

y=40-28

y=12

Therefore, x=28 , y=12

Similar questions