Question

X-Y=43 and XY=50 so find X and Y

Answer 1

Answer:

X-Y=43

=X=43+Y------(1)

XY=50-----(2)

Therefore, puttin equation (1) in (2)

(43+Y)Y=50

43Y+Y²=50

Y²+43Y-50=0

therefore according to the formula

(-b±√(b²-4ac))/2a

Where,

a=1

b=43

c=50

(-43±√(43²-4×1×50))/2×1

Therefore Y=-1.19 & -41.8

So X=43+(-1.19)= 41.8

X= 43+(-41.8)= 1.2

Answer 2

X =44.13 For Y= 1.13 and X = -1.132 for

Y = -44.132

Given:

X-Y=43 and XY=50

To find:

X and Y

Explanation:

X-Y=43

   X = 43+Y

Put this value in below equation.

  XY=50

 (43+Y)Y =50

  Y² +43Y =50

 Y² +43Y -50 =0

This is the quadratic equation the root of equation is given by.

Root of the equation = $\frac{-b \ +\sqrt{b^2 - 4ac} }{2a}$ , $\frac{-b \ -\sqrt{b^2 - 4ac} }{2a}$

Here a = 1 , b=43. c = -50

Root of the equation =$\frac{- \43 +\sqrt{43^2 - 4\times 1(-50)} }{2(1)}$ , $\frac{- \43 -\sqrt{43^2 - 4\times 1(-50)} }{2(1)}$

            Y = 1.13,-44.132.

Put this value in above equation.

X =  43+Y = 43+1.13 = 44.13 For Y= 1.13

and for Y = -44.132 X =  43+Y = 43-44.132 = -1.132

To learn more....

1)The sum of the roots of a quadratic equation is 3 while the sum of the squares of its roots is 7. find the equation.

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2)Show that the product of the roots of a quadratic equation is ‘c/a’.

https://brainly.in/question/5483738