Question

x+y=48 x+4=5/2(y+4)​

Answer 1

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QUESTION: $\boxed{x+y=48}$  &

                    $\boxed{x+4=\frac{5}{2(y+4)}}$[let this be equation (i)]

Solution:-

step-1

From the First Equation we can say that if,

$x+y=48$ ,

then,

$x=48-y$, [Let this be equation(ii)]

step-2(substitute the values)

Putting the value of x from equation (ii) in equation (i),

$x+4=\frac{5}{2(y+4)}$

$\implies 48-y+4=\frac{5}{2(y+4)}$

$\implies 52-y=\frac{5}{2y+8}$

$\implies (52-y)(2y+8)={5}$

$\implies (104y+416-2y^2-8y)={5}$

$\implies (-2y^2+96y+416)={5}$

$\implies 2y^2-96y-416=-5}$

$\implies 2y^2-96y-416+5=0$

$\implies 2y^2-96y-411=0$