x+y=_4andxy=2,then find the value of x^2+y^2
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1
Answer:
(x+y)²=x²+y²+2xy
(-4)²=x²+y²+2*2
16=x²+y²+4
12=x²+y²
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theprimus2446:
bro it was x^2 +y^2
Answered by
0
we know that,
x^2 + y^2 = (x+y)(x^2 - xy +y^2)
so, now...
=(x+y)^2 =4^2
=(x+y)(x^2 - xy +y^2)=16
= 4(x^2 -2+ y^2)=16
= x^2 + y^2 -2 =16-4
=x^2 + y^2 =12+2
=x^2 + y^2 = 14
L.H.S. = R.H.S.
HECNCE VERIFIED
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