Question

x+y-5=0 and 2x-3y-4=0 solve by cross multiplication method​

Answer 1

Answer:

$x +y - 5 = 0 \: .........(1) \\ 2x -3y -4 = 0 \: ..........(2) \\ \frac{(a1 = 1) = (b1 = 1) = (c1 = - 5)}{(a2 = 2) = (b2 = - 3) = (c2 = - 4)} \\ x = \frac{b1c2 - b2c1}{a1b2 - a2b1} \\y = \frac{c1a2 - c2a1}{a1b2 - a2b1} \\ x = \frac{(1)( - 4) - ( - 3)( - 5)}{(1)( - 3) - (2)(1)} \\ x = \frac{ - 4 - 15}{ - 3 - 2} \\ x = \frac{ - 19}{ - 5} \\ x = \frac{19}{5} = value \: of \: x \\ y = \frac{( - 5)(2) - ( - 4)(1)}{(1)( - 3) - (2)(1)} \\ y = \frac{ - 10 + 4}{ - 5} \\ y = \frac{ - 6}{ - 5} \\ y = \frac{6}{5} = value \: of \: y$

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