Math, asked by nikhilaggarwal386, 18 days ago

x+y=5,2x-3y=14 by substution method​

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Answered by arman6939
1

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Answered by Anonymous
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{\huge{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{purple}{\bf{\color{yellow}{Answer}}}}}}

 \sf{x + y = 5 \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ... (i)} \\  \sf{2x - 3y = 14 \:  \:  \:  \:  \:  \:  \:  \: ...(ii)} \\ \\  \sf{by \: using \: substitution \: method : }   \\  \sf{x + y = 5} \\  \sf{x = 5 - y } \\  \sf{putting \: this \: value \: of \: x \: in \: eq {}^{n} (ii)} \\  \sf{2x - 3y = 14 \:  \:  \:  \:  \:  \:  \: ...(ii)} \\  \sf{2(5 - y) - 3y = 14} \\  \sf{10 - 2y - 3y = 14} \\  \sf{10 - 5y = 14} \\  \sf{ - 5y = 14 - 10} \\  \sf{ - 5y = 4} \\  \sf{y =  \frac{4}{ - 5} } \\   \boxed{\sf{y =  -  \frac{4}{5} }}

 \sf{now : }  \\  \sf{putting \: value \: of \: y \: in \: eq {}^{n} (i)} \\ \sf{x  +  y = 5} \\  \sf{x  +  ( -  \frac{4}{5} ) = 5} \\ \sf{x = 5 -  \frac{4}{5} } \\  \sf{x =  \frac{25 + 4}{5} } \\    \boxed{ \sf{x =  \frac{29}{5} }}

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