Question

x+y=5 and 2x-3y=4
solve this by elimination method​

Answer 1

Answer:

19/5

Step-by-step explanation:

x + y = 5 ( equation 1 )

2x - 3y = 4 ( equation 2 )

Now,

multiplying (eq.1) by 2 and subtracting (eq.2) from ( eq.1 )

(2x + 2y = 10) - (2x - 3y = 4 )

=> 2x + 2y - 2x + 3y = 6

=> 5y = 6

=> y = 6/5

Putting the value of y in ( eq.1 )

=> x+ y = 5

=> x + 6/5 = 5

=> x = 5 - 6/5

=> x = 19/5

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Answer 2

Question :- x+y=5 , 2x-3y=4 solve by elimination method .

Solution :-

→ x + y = 5 ----------- Eqn.(1)

→ 2x - 3y = 4 ----------- Eqn.(2)

Multiply Eqn.(1) by 2 and then, subtracting Eqn.(2) from the result we get,

→ 2(x + y) - (2x - 3y) = 2 * 5 - 4

→ 2x + 2y - 2x + 3y = 10 - 4

→ 2x - 2x + 2y + 3y = 6

→ 5y = 6

→ y = (6/5) .

putting value of y in Eqn.(1) now,

→ x + (6/5) = 5

→ x = 5 - (6/5)

→ x = (25 - 6)/5

→ x = (19/5) .

Hence, x is equal to (6/5) and y is equal to (19/5).

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if a^2+ab+b^2=25

b^2+bc+c^2=49

c^2+ca+a^2=64

Then, find the value of

(a+b+c)² - 100 = ...

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