x+y=5 and 2x-3y = 5
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X+y= 5
Add the -y both sides
X+y -y = 5 - y
x = -y+5
2) 2x -3y = 5
Add 3y to both sides
2x-3y+3y= 5 + 3 y
2x= 3y+5
Divide both sides by 2
2x/2 = 3y + 5 / 2
X = 3/2y+5/2
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Answer:
Given:
- x+y=5 and ......equ(1)
- 2x-3y = 5.......equ(2)
To find :
- value of 'x' and 'y'.
Pre- requisite knowledge:
Elimination method: In this method we would first eliminate one variable and the find the solution of the next.
Solution:
multiply 3 in equ(1)
⇒ 3x +3y = 15 .....equ((3)
equate equ(2) and equ(3)
⇒ 2x - 3y = 5
3x + 3y = 15
..............................
we get, 5x = 20
⇒ x = 4
substitute this in equ(1)
⇒ x + y = 5
or , 4 + y = 5
⇒ y = 1
Therefore, the value of 'x' is 4 and that of 'y' is 1
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