Question

X + y = 5 x y. / 3 X + 2 Y = 13 xy​
std 10 ncert elimination method

Answer 1

Answer:

Answer is in the above image!!!!

Explanation:

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Answer 2

AnsWer:-

↝x+y=5xy→÷xy

↝$\frac{\cancel{x}}{\cancel{x}y}$+$\frac{\cancel{y}}{x \cancel{y}}$=$\frac{5 \cancel{xy}}{\cancel{xy}}$

↝$\frac{1}{y}$+$\frac{1}{x}$=5

[Let 1/y=u and let 1/x=v]

➜u+v=5-(1)

↝3x+2y=13xy

↝$\frac{3 \cancel{x}}{\cancel{x}y}$+$\frac{2 \cancel{y}}{x \cancel{y}}$=$\frac{13 \cancel{xy}}{\cancel{xy}}$

↝$\frac{3}{y}$+$\frac{2}{x}$=13

↝3×($\frac{1}{y}$)+2($\frac{1}{x}$)=13

[Let 1/y=u and let 1/x=v]

➜3u+2v=13-(2)

✪Multiply eq-(1) with 3✪

↝3u+3v=15-(3)

▼Subtract -(3) and -(2)▼

↝3u+3v=15

↝3u+2v=13

★Signs Change★

➜v=2-(4)

♦Using (4) in (2)♦

↝3u+2×2=13

↝3u+4=13

↝3u=13-4

↝u=$\frac{\cancel{9}}{\cancel{3}}$

➜u=3-(5)

•1\y=u

☞y=⅓

•1\x=v

☞x=½

$\rule{200}{2}$