X+√Y=5 , √X+Y=9, find the value of X and Y
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If √x+y=11, and x+√y=9 , be a simultaneous equation, then how can I find the value of x and y?
Education program with HCL.
x−−√+y=11⋯(1) x≥0
and x+y√=9⋯(2) y≥0
Multiply Eq.(2) by 1x−−√
x−−√+y√x−−√=9x−−√⋯(3)
Subtract (3) from(1)
y−y√x−−√=11−9x−−√
y×x−−√−y√=11×x−−√−9
Since x−−√=11−y
⟹y×(11−y)−y√=11(11−y)−9
y√=−y−11)2+9
y=(y−11)4+81−18(y−11)2
⟹(y−11)4−18(y−11)2−(y−11)+70=0
On solving this Equation you will get four positive real value of y.
Then find x.
Only x≥0 &y≥0 pair are solution of the equation.
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