x + y = 5,xy =3 .find x-y
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Given equation is x + y = 5 ---- (1)
Given xy = 3 --- (2)
On squaring equation (1) on both sides, we get
= > (x + y)^2 = (5)^2
= > x^2 + y^2 + 2xy = 25
= > x^2 + y^2 + 2(3) = 25
= > x^2 + y^2 + 6 = 25
= > x^2 + y^2 = 25 - 6
= > x^2 + y^2 = 19.
Therefore:
= > (x - y)^2 = x^2 + y^2 - 2xy
= 19 - 2(3)
= 13.
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