x+y=5 , xy = 6 , x3 - y3 = ?...
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x+y=5
= y=5-x --(1)
xy=6
= (x)(5-x)=6
5x-x^2 =6
x^-5x+6=0
on solving x=2 and x=3
therefore from (1)
y=2 or y= 3
there fore x^3-y^3= 2^3 -3^3
=8-27
=-19
or
x^3-y^3=3^3-2^3
=27-8
=19
therefore x^3-y^3= 19 or -19
= y=5-x --(1)
xy=6
= (x)(5-x)=6
5x-x^2 =6
x^-5x+6=0
on solving x=2 and x=3
therefore from (1)
y=2 or y= 3
there fore x^3-y^3= 2^3 -3^3
=8-27
=-19
or
x^3-y^3=3^3-2^3
=27-8
=19
therefore x^3-y^3= 19 or -19
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