X+y=50
Y+Y+Y=120
X+Z=25
Z=?
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Answer:
Let's name the given equations
x+y = 50 (1)
y+y+y = 120 (2)
x+z= 25 (3)
On solving (3), we get
y+y+y = 120
--> 3y = 120
--> y = 120/3
--> y = 40
Putting y=40 in (1)
x+y = 50
--> x+ 40 = 50
--> x = 50-40
--> x = 10
Putting x = 10 in (3)
x+z= 25
--> 10 + z = 25
--> z= 25- 10
--> z = 15
Thus, Z = 15
Hope it helps!
:)
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