Question

X+y=50,y+y+y=120,X+z=35then Z=? please answer ​

Answer 1

Answer:

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Answer 2

Given, X+y= 50 , y+y+y=120 , X+z=35

⟹Y+Y+Y=120

⟹3Y=120

⟹Y =$\large \frac{120}{3}$

⟹Y = 40

Substituting the value of Y in:

⟹X+Y=50

⟹X+40=50

⟹X=50-40

⟹X=10

Substituting the value of X in the equation:

⟹X+Z=35

⟹10+Z=35

⟹Z=35-10

⟹ Z=25

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